Find the exact real value of arccos(-sqrt(2)/2).

 arccos(-sqrt(2)/2). range of cos − 1 ( x )=[ 0 , π ]
= arccos(0.706 )
=45 degrees
hope  this helps

Ais the correct answer

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.