Wade and Alexandra are 240 feet apart when they start walking toward one another. Alexandra walks twice as fast as Wade so whenever Wade travels x feet, Alexandra travels 2x feet. Let z represent the number of feet Wade has traveled since he started walking toward Alexandra.

The initial distance between Wade and Alexandra is 240ft.

They walk towards each other.

Alexandra walks twice as fast as Wade.

Now, because they are walking towards each other, when the distance walked by both of them equals 240 ft, they will meet.

Then:

if Wade walks z ft, Alexandra walks 2*z ft.

So we have the equation:

Distance that Wade walked + Distance that Alexandra walked = 240ft

z + 2*z = 240ft

3*z = 240ft

z = 240ft/3 = 80ft

They will meet when Wade walks 80ft.

Complete question :

Wade and Alexandra are 240 feet apart when they start walking toward one another. Alexandra walks twice as fast as Wade so whenever Wade travels x feet, Alexandra travels 2x feet. Let z represent the number of feet Wade has

traveled since he started walking toward Alexandra.

Write an expression in terms of z to represent the total number of feet Wade and Alexandra have walked toward one another.

b. Write an expression in terms of z to represent the distance (in feet) between Wade and Alexandra

Kindly check explanation

Step-by-step explanation:

Given that:

Initial distance between Wade and Alexandra = 240 feets

Alexandra walks twice as fast as wade :

Feets traveled by Wade = x

Feets traveled by Alexandra = 2x

Let z = feets traveled by wade since he started walking towards Alexandra

A.) Number of feets they've traveled towards one another in terms of z:

Number of feets traveled by wade = z

Number of feets traveled by Alexandra = 2z

Hence, total feets traveled towards one another :

(distance covered by Wade + distance covered by Alexandra)

= ( z + 2z) = 3z feets

B.) Distance between Wade and Alexandra:

Initial distance - distance covered

(240 - 3z) feets

b. hoped i'm right lol

step-by-step explanation: