A gasoline tanker is filled with gasoline which weighs 45.93 lb/ft3. The dispensing valve at the base is jammed shut, forcing the operator to empty the tank via pumping the gas to a point 1 ft above the top of the tank. Assume the tank is a perfect cylinder, 20 ft long with a diameter of 7.5 ft. Set up the integral(s) that would allow you to find how much work is performed in pumping all the gasoline from the tank?

The appropriate answer will be "Y = 157.09 N/m³".

Step-by-step explanation:

The given values are:

Diameter

= 7.5 ft

= 0.3048 meter

Height

= 20ft

= 6.096

Weight density

= 45.93 lb/ft³

= 16.0184634 kg/m³

Acceleration

= 9.807 m/s2

As we know,

The specified density of weight can be expressed as:

⇒  Specific weight = density × acceleration

i.e.,

⇒  

On substituting the estimated values in the above expression, we get

⇒      

⇒      

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

(3x-8) or (3x+8)

step-by-step explanation: