a. The distance equation is D = RT, where D is distance R is rate (speed) T is time If cheetah travels at max speed, 70 mph, we can say D = 70t There are 60 minutes in 1 hours, so the distance in miles per minute is: D = 1.167t miles per minute b. Given t = 10 minutes, the distance covered using formula would be D = RT D = 1.167 * 10 = 11.67 miles c. Since Cheetah traveled at max speed (70mph) for the first leg of 8 minutes, the distance covered would be: D = RT D = 1.167 * 8 D = 9.33 miles d. Next leg of 8 minutes would be at 40mph, to get that in minutes, we divide by 60, so rate would be 40/60. Hence, distance covered is: D = RT D = (40/60) * 8 = 5.33 miles e. The distance traveled in first 8 minutes is 9.33 The distance traveled in second 8 minutes is 5.33, Hence, the more distance is 9.33 - 5.33 = 4 miles f. To justify if 9.33 is actually 1.75 times that of 5.33, we multiply 5.33 by 1.75 and see if it is 9.33. So 1.75 * 5.33 = 9.33 [in fact, it is!] Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.