A veterinarian is changing the diets of two animals, Simba and Cuddles. Simba currently consumes 1,520 Calories per day. That number will increase by 130 Calories each day. Cuddles currently consumes 3,380 Calories a day. That number will decrease by 180 Calories each day. The patterns will continue until both animals are consuming same number of Calories each day. In how many days will that be? How many Calories will the animals be consuming each day then? In days Simba and Cuddles will be consuming the same amount of calories. Simba and Cuddles will be consuming calories each day.

6 days ; 2300 calories

Step-by-step explanation:

Given the following :

Current consumption :

Simba = 1520 calories per day

Increases by 130 calories per day : After d days ;

S(d) = 1520 + 130d

Where ; d = number of days

Cuddle = 3380 calories

Decreases by 180 calories each day; after d days ;

S(d) = 3380 - 180d

Pattern continues until they both consume same number of calories each day

S(d) = C(d)

1520 + 130d = 3380 - 180d

130d + 180d = 3380 - 1520

310d = 1860

d = 6

Number of calories they will be consuming them ;

Using : S(d) = 3380 - 180d

S(6) = 3380 - 180(6)

S = 3380 - 1080

S = 2300

They will be consuming 2300 calories by then.

you cant answer this dummy

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05