Which of the following numerators would appear in the numerator of the quadratic formula when solving the following equation? 2x^2 + 5x - 12 = 0

-5± √71
-5±11
5±11

-5±11

Our equation: 2x^2 + 5x - 12 = 0

Formula: x=-b±√b^2-4ac/2a

Formula: ax^2+bx+c=0

variable a=2 DO NOT INCLUDE x^2

variable b=5 DO NOT INCLUDE x

variable c=-12

x=-5±√5^2-4*2*-12/2*2

x=-5±√25+96/4

x=-5±√121/4

x=-5±11/4

-5±11 is the answer since were looking for any of the occurring numorators. Hope this helped!

this is a good question! i’ll do some research and what i find, i’ll contact you asap when i have something! ✊

8(1/6)

step-by-step explain:

49/6= 48

8 (1/6)