Solve 3(4y+6) ≤ −2(3−6y)

0 ≤ -24 ( can't be true)

Step-by-step explanation:

3(4y+6) ≤ -2(3-6y)

12y + 18 ≤ -6 + 12y

0 ≤ -24

not true ( can't be true)

The statement is false for any value of y.

Step-by-step explanation:

3(4y+6) ≤ −2(3−6y)

Step 1: Distribute

12y + 18 ≤ -6 + 12y

Step 2: Cancel out equal terms on both sides

12y + 18 ≤ -6 + 12y

-12y -12y

18 ≤ -6

There is no more y variable.

Therefore the statement is false for any value of y.

x coordinate is none

step-by-step explanation: