Passes through (0, 2) and has slope of -5/3.

y = -5/3x + 2

Step-by-step explanation:

I am not exactly sure what your question is, but to find the equation of the line, you can plug in the x and y coordinates to the template which is y=mx+b. Since you already have the slop (m) you just need to find b which you can do by setting up the equation: 2 = -5/3*0 + b, and solving for b. This gives you a value of 2 for b. So your final equation would be y = -5/3 + 2.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

it is 570

step-by-step explanation: