What is the equation of a line that contains point (3, –1) and is PERPENDICULAR to 12x + 4y = 8?

x - 3y = 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

12x + 4y = 8 ( subtract 12x from both sides )

4y = - 12x + 8 ( divide all terms by 4 )

y = - 3x + 2 ← in slope- intercept form

with slope m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = , thus

y = x + c ← is the partial equation

To find c substitute (3, - 1) into the partial equation

- 1 = 1 + c ⇒ c = - 1 - 1 = - 2

y = x - 2 ← in slope- intercept form

Multiply through by 3

3y = x - 6 ( subtract 3y and add 6 to both sides )

x - 3y = 6 ← in standard form

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e