Akbar, Ali and Arman are 3 brothers. The ratio of Akbar's age to Arman's age is 1 : 2 and the ratio of Akbar's age to Ali's age is 2 : 5. If the eldest boy is 10 years old, how old is the youngest one?

The age of the youngest one is 4.

Ratio is used to determine the relationship between numbers. It shows the frequency of the number of times that one value is contained within other value(s).

The  ratio of Akbar's age to Arman's age is 1 : 2 and the ratio of Akbar's age to Ali's age is 2 : 5 or 1: 2.5 expressed in its simplest form. This means that the oldest is Ali and the youngest is Akbar.

If Akbar's age is 10, then Ali's age is 10 / 2.5 = 4.

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The youngest one is 4 years

Step-by-step explanation:

The ratio of Akbar's age to Ali's age is 2 : 5

= 2/5

The oldest = Ali

Hence, let's represent Akbar's age as y

2/5 = y/10

Cross Multiply

5y = 2 × 10

y = 20/5

y = 4 years old.

Akbar's age = 4 years old.

Akbar's age to Arman's age is 1 : 2

= 1/2

Hence, let's represent Arman's age as z

1/2 = 4/z

Cross Multiply

= z = 2 × 4

z = 8 years old

Arman's age = 8 years old.

Therefore, the age of the youngest = 4 years old.