An architect measures a beam to be 96.55 centimeters long, with an accuracy of plus or minus 0.02 centimeter. Which equation can be used to find the limits of the actual length of the beam? |x−96.55|=0.02start absolute value x minus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55−0.02|=xstart absolute value 96 point 5 5 minus 0 point 0 2 end absolute value is equal to x |x+96.55|=0.02start absolute value x plus 96 point 5 5 end absolute value is equal to 0 point 0 2 |96.55+0.02|=x