Arectangle with an area of 240 in2 has a length 10 inches shorter than five times its width. which equation could be used to solve for the length of the rectangle?

The equation which can be used to solve for the length of the rectangle :  x² - 2x - 48 = 0

Step-by-step explanation:

Let width of the rectangle be x inches

Now, The rectangle has length 10 inches shorter than five times its width

⇒ Length of rectangle = 5x - 10

Now, Area of rectangle is given to be : Area = 240 inches²

Also, Area of the rectangle is given by the formula : Area = Length × Width

⇒ 240 = (5x - 10) × x

⇒ 5x² -10x = 240

⇒ 5x² - 10x - 240 = 0

⇒ x² - 2x - 48 = 0

Therefore, The equation which can be used to solve for the length of the rectangle :  x² - 2x - 48 = 0

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%