Use the figure to write the segment addition postulate, write an equation and solve for x.

5. x = -1

6. x = 2

Step-by-step explanation:

5. AB = 5

BC = 2x + 6

AC = x + 10

AB + BC = AC (segment addition postulate)

5 + 2x + 6 = x + 10 (substitution)

Collect like terms

5 + 6 + 2x = x + 10

11 + 2x = x + 10

2x - x = - 11 + 10

x = -1

6. AB = 9x + 7

BC = -3x + 20

AC = 39

AB + BC = AC (segment addition postulate)

(9x + 7) + (-3x + 20) = 39 (substitution)

Solve for x

9x + 7 - 3x + 20 = 39

Collect like terms

9x - 3x + 7 + 20 = 39

6x + 27 = 39

Subtract 27 from both sides

6x + 27 - 27 = 39 - 27

6x = 12

Divided both sides by 6

6x/6 = 12/6

x = 2

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5