Use the zero product property to find the zeros of the quadratic function. b(x) = (x + 4) (2x - 3)

AnswWhen f(x) is divided by x-1 and x+1 the remainder are 5 and 19 respectively.

∴f(1)=5 and f(−1)=19

⇒(1)  

4

−2×(1)  

3

+3×(1)  

2

−a×1+b=5

and (−1)  

4

−2×(−1)  

3

+3×(−1)  

2

−a×(−1)+b=19

⇒1−2+3−a+b=5

and 1+2+3+a+b=19

⇒2−a+b=5 and 6+a+b=19

⇒−a+b=3 and a+b=13

Adding these two equations, we get

(−a+b)+(a+b)=3+13

⇒2b=16⇒b=8

Putting b=8 and −a+b=3, we get

−a+8=3⇒a=−5⇒a=5

Putting the values of a and b in

f(x)=x  

4

−2x  

3

+3x  

2

−5x+8

The remainder when f(x) is divided by (x-2) is equal to f(2).

So, Remainder =f(2)=(2)  

4

−2×(2)  

3

+3×(2)  

2

−5×2+8=16−16+12−10+8=10er:

Step-by-step explanation:

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step-by-step explanation: