Triangle E F G. Side E F is 6 meters, F G is 5 meters, E G is 7 meters. Angle F is 87 degrees and angle G is 58 degrees. Triangle K L J. Side K L is 28 meters, L J is 24 meters, J K is 20 meters. Angle K is 58 degrees, L is 35 degrees, J is 87 degrees. What can you conclude about these triangles? Check all that apply.

F(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.

Iwill arward ! , i if bt ≅ eu , bu ≅ et , prove: ∠b ≅ ∠e. fill in the blanks: draw segment ut ≅ bt≅ bu ≅ △ubt ≅ △