1) 6(d-2) - 2(d+2) = 2) (e-3) - 4 (2e +1) =
3) (f -1) - (f-1) + 1 =
4) 2(7-9g) - 3(4-2g) =
5) 5a(6 + 2b) + 6ab - 7 =
6) 2x(3y - 1) + 2x(3y + 1) =
7) 6p(q+9) - 3p(2p-1) =

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answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1