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(WITH AN EXPLANATION)
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Factors: (x²y+6)(y²-11)

Step-by-step explanation:

Here's the original equation.

x²y³ - 11x²y + 6y² - 66

Let's separate it into two groups to make it easier.

(x²y³ - 11x²y) + (6y² - 66)

Let's take a look at (x²y³ - 11x²y) first. Do we notice anything that can be removed from the parentheses?

Yes, x²y can be taken from both polynomials to simplify the contents of the parentheses.

Both polynomials have x² and both have at least one y. Combine that to get x²y. That means that within the parentheses y² and - 11 will be left.

So  (x²y³ - 11x²y) becomes x²y (y²-11)

This works because if we multiply x²y * (y² - 11) we get (x²y³ - 11x²)

Let's apply this same idea to (6y² - 66).

6 is the only thing in common between the two polynomials.

If we follow the same steps we get 6 (y²-11).

Notice how when we simplified both groups they each had something on the outside and (y² - 11) in the parentheses?

So lets combine the things that were on the outside of both (y² - 11).

What was on the outside of each? x²y was on the outside for the first one, and 6 for the outside of the second one.

This means that if we combine everything and simplify, the factors we have are (x²y+6)(y²-11).

If you want to confirm, work your way backwards using the distributive property. You'll find that when you multiply (x²y+6) * (y² -11) you'll get = x²y³ - 11x²y + 6y² - 66. That was the original equation, so we know that these are the factors.

Hope that helps!