Can someone answer these questions & explain how to get the answer will mark brainlest!

25) 3 = 5 + secΘ where we have 2 possible values of Θ (2π/3 or 4π/3)

3 = 5 + sec (2π/3)

3 = 5 + sec (120 degrees)

3 = 5 + (-2)

3 = 3

theta =  4π/3

3 = 5 + sec (240 degrees)

3 = 5 + (-2)

3 = 3

Therefore, the equation is true for both 2π/3 and 4π/3

27) -2 SinΘ = -1                {π/6 , 5π/6}

-2 * sin(π/6) = -1

sin(π/6) = 1/2

1/2 = 1/2

LHS = RHS

theta  = 5π/6

-2 sin(5π/6) = -1

sin(5π/6) = 1/2

1/2 = 1/2

LHS = RHS

Kindly Mark

hope this .

r3t40