An equation of a line with a slope of - 4/5 that passes through the point (5,3)

y = -(4/5)x + 7

Step-by-step explanation:

recall that the point-slope form of a linear equation is given as

y - y₁ = m (x - x₁)

in our case, we are given

slope, m = -4/5

and a point (x₁, y₁) = (5,3)

hence we simply substitute these values into the equation

y - y₁ = m (x - x₁)

y - 3 = -(4/5) (x - 5)    (we will simplify this to convert to slope-intercept form)

y - 3 = -(4/5) (x) - (-4/5)(5)

y - 3 = -(4/5)x +4   (add 3 to both sides)

y = -(4/5)x +4  +3

y = -(4/5)x + 7

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

on plase n