Find the perimeter of the quadrilateral whose vertices are as follows: (-1,1), (-2,4), (-4,2),(-3,-1).

Transcribed Image Text from this Question. 13. Find the perimeter of the quadrilateral whose vertices are as follows. +F (-1,1).(-2,4).(-4,2),(-3,-1) ...

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180