Give the standard form of the equation of the circle with endpoints of a diameter at (-6, 5) and(-2, —3).

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Step-by-step explanation:

(x−h)2+(y−k)2=r2 ( x - h ) 2 + ( y - k ) 2 = r 2 is the equation form for a circle with r radius and (h,k) as the center point. In this case, r=√26 and the center point is (2,7) . The equation for the circle is (x−(2))2+(y−(7))2=(√26)2 ( x - ( 2 ) ) 2 + ( y - ( 7 ) ) 2 = ( 26 ) 2 . We know that the general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius. So add 21 to both sides to get the constant term to the righthand side of the equation. Then complete the square for the y terms. The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius. Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet. You can also use the circumference and radius equation.

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