Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of options. Mike has twice the total number of points decreased 201. how many points do they have altogether?

108points

Step-by-step explanation:

Let Caleb score be x and that of Mike be y. If Caleb and Mike both score the same amount of points in a game, then x = y.

The total number of option = x+y

Now, If Caleb has fifteen less than the total number of options, then;

x =(x+y)-15

x -(x+y)+15 = 0

x-x-y = -15

-y = -15

y = 15

Also if Mike has twice the total number of points decreased 201, then;

y = 2(x+y)-201

Since y = 15

15 = 2(x+15)-201

15 = 2x+30-201

15 = 2x-171

2x = 15+171

2x = 186

x = 186/2

x = 93

The total number of points they have altogether is x+y

x+y = 15+93

x+y = 108

Hence the total points that they have altogether is 108points

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24