PLEASE HELP ME TO DO Q 2b pleaseee

x = 2 log 2 / (log 5 − log 2)

x = log 4 / log(2.5)

Step-by-step explanation:

2ˣ⁺² = 5ˣ

Take log of both sides.

log(2ˣ⁺²) = log(5ˣ)

Use exponent property.

(x + 2) log 2 = x log 5

Distribute.

x log 2 + 2 log 2 = x log 5

Subtract x log 2 from both sides.

2 log 2 = x log 5 − x log 2

Factor out x.

2 log 2 = x (log 5 − log 2)

Solve for x.

x = 2 log 2 / (log 5 − log 2)

If you want, you can simplify further:

x = log 4 / log(2.5)

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.