Which sequences of transformations applied to shape I prove that shape I is similar to shape II? Areflection across the x-axis, followed by a reflection across the y-axis, and then a dilation by a scale factor of 0.5
B a 90° counterclockwise rotation about the origin, and then a dilation by a scale factor of 0.5
C a 180° counterclockwise rotation about the origin, and then a dilation by a scale factor of 0.5
Da translation 2 units down and 5 units left, and then a dilation by a scale factor of 0.5

i need a picure

step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

50-60=10

step-by-step explanation:

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.