Correct answer gets THANKS, 100 points and Brainliest Answer! Please help me! There are two bags with colored marbles. In the 1st bag there are 3 red, 2 blue and 1 green marble. In the 2nd bag there are 1 blue and 4 red marbles.

1. What is the probability of drawing the same colored marble? Explain. P(same color)=

2. What is the probability of drawing a blue marble? Explain. P(blue)=

3. What is the probability of NOT drawing the same colored marble? Explain. P(not same color)=

the probability of drawing the same color is 11 / 3 for red 11/2 for blue 11/1 for green

Step-by-step explanation:

its 11/8 for red 11/9 for blue and 11/10 for green

Their is a 50% chance of you picking red out of the first bag and a 80% of red in the second bag. The probability of drawing a blue in the frst bag is 33% and 16% in the second bag.

Step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1