One rectangle has a length of 4x+2 and a width of 2x. A square has side lengths that are 4x. If the perimeter of the rectangle and the square are equal, what are the dimensions of the square?

Side lengths are 2

Step-by-step explanation:

Perimeter of the rectangle would be = 4x+2+4x+2

Simplified= 8x +4

Perimeter of the square=4x+4x+4x+4x

Simplified 16x

16x=8x+4

Take away 8x

8x=4

Then divide by 8

X=0.5

The squares side lengths are 4x, so 0.5 times 4 is 2.

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116