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Mathematics, 25.09.2020 22:01 cubist7472

Find the smallest solution to negative 5 e superscript negative 4 x plus 2 baseline plus 3 equals one half log left parenthesis x squared plus 1 right parenthesis and describe the steps you used. Round your answer to three decimals.

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Find the smallest solution to negative 5 e superscript negative 4 x plus 2 baseline plus 3 equals on...
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