Of 24 pounds of salt water, 8% is salt. Of another mixture, 4% is salt. How many pounds of the second mixture should be added to the first mixture in order to get a mixture of 5% salt. Write an equation to represent the total amount of salt water, in pounds, present. Let x represent the total amount of 4% salt water, let y represent total amount of the end 5% salt solution.

(0.08 × 24) + (0.04 * x) = 0.05 * (x + 24)

Step-by-step explanation:

Given the following :

Amount of salt water = 24 pounds ;% of salt = 8% = 0.08

Of another mixture ; salt = 4% = 0.04

Total amount of 4% salt water = x

y = total amount of the end 5% solution

Amount of salt in first and second mixture = 5% of salt in end solution

Amount of salt in first mixture = 0.08 × 24

Amount of salt in second mixture = 0.04 * x

Amount of salt in end solution = 0.05 * (total amount of mixture) = 0.05 * (x + 24)

(0.08 × 24) + (0.04 * x) = 0.05 * (x + 24)

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64