Which quantity could go in the blank to make the equation below true r+3r+_=6r

2r

Step-by-step explanation:

r+3r+_=6r

Let's simplify this first.  Subtract (r + 3r), or 4r, from both sides, obtaining

0 + _ = 2r

Then the quantity 2r, when placed in the blank, makes the equation true.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x