HELP PLS!! Find the distance between (-3, 11) and (-6, 4). Round to the nearest tenth.

Your input: find the distance between P=(−3,11)

P

=

(

−

3

,

11

)

and Q=(−6,4)

Q

=

(

−

6

,

4

)

.

The distance between two points is d=(x2−x1)2+(y2−y1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√

d

=

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

.

We have that x1=−3

x

1

=

−

3

, y1=11

y

1

=

11

, x2=−6

x

2

=

−

6

, y2=4

y

2

=

4

.

So, d=(−6−(−3))2+(4−(11))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=58‾‾‾√

d

=

(

−

6

−

(

−

3

)

)

2

+

(

4

−

(

11

)

)

2

=

58

.

d=58‾‾‾√≈7.61577310586391

d

=

58

≈

7.61577310586391

.

Step-by-step explanation:

Hey! Got this off of someone else ages ago.. hope this helps tho