Which point is an x-intercept of the quadratic function f(x)=(x-8)(x+9)

Step-by-step explanation:

An x-intercept of a function occurs when f(x) = 0.

In f(x) = (x-8)(x+9), f(x) will be 0 if either (x-8) is 0 or (x+9) is 0.

Hence, f(x) = 0 when x = 8 or x = -9.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer;

the correct answer

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have a nice day < 3