One model for car depreciation is as follows, where C is the original cost, V is the value of the car after t years, and is the rate of depreciation

V=C(1-r)^t

of the original cost of the car was $21,000 and the rate of depreciation is 15%, what will be the value of the car after 5 years?

[Round to the nearest dollar.)

A $19,472

B. $3,150

C$9,318

D. $17,850

C $9,318

Step-by-step explanation:

In order to find the answer you have to use the formula provided to calculate the value of the car after t years:

V=C(1-r)^t

C=$21,000

r=15%

t=5

V=21,000*(1-0.15)^5

V=21,000*0.4437

V=9,318

According to this, the answer is that the value of the car after 5 years is $9,318.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

the answer is 2/54

step-by-step explanation: