Points P, Q,R, and S are collinear. Point Q is between P and R, R is between Q and S. If PS=25, and PR=19, what is the value of QR

Step-by-step explanation:

The questions is incomplete. Here is the complete question.

Points P,Q,R,and S are collinear. Point Q is between P and R, R is between Q and S where  PQ ≈ RS. If PS=25, and PR=19, what is the value of QR

If points P,Q,R,and S are collinear, this means that the four points lies on the same straight line.

If Point Q is between P and R, then PQ+QR = PR 1

Also if R is between Q and S, then QR+RS = QS 2

Given

PS=25

PR=19

RS = PS-PR

RS = 25-19

RS = 6

Since PQ ≈ RS

Hence PQ = RS = 6

From equation 1;

PQ+QR = PR

substituting the resulting values

6+QR = 19

QR = 19-6

QR = 13

Hence the value of QR is 13

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hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)