The perimeter of a rectangle is found by multiplying the sum of the length, shown as I, and the width, shown as w, by 2. The length of a certain rectangle is 20. Which
inequality shows that the perimeter of this rectangle is less than 57 units?
A.2 (20+w) > 57
B.2 (20 + w) < 57
C.2 (20) (w) > 57
D.2 (20) (w) < 57

  B.  2(20 + w) < 57

Step-by-step explanation:

Only choices B and D show something "less than 57". Of those, only choice B shows a sum of length and width.

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5