You invested $28,000 in two accounts paying 6% and 8% annual interest, respectively. If the total interest earned for the year was $2100, how much was invested at each rate?

At 6% interest rate, amount invested = $7000

At 8% interest rate, amount invested = $21000

Step-by-step explanation:

Let amount invested in one account be x and amount invested in the other be y.

Thus;

x + y = 28000 - - - - (eq1)

Interest rate for them are 6% and 8% annually.

We are told that total interest earned for the year was $2100

Thus;

0.06x + 0.08y = 2100 - - - - (eq 2)

Make x the subject in equation 1.

x = 28000 - y - - - - (eq 3)

Put 28000 - y for x in eq 2

0.06(28000 - y) + 0.08y = 2100

1680 - 0.06y + 0.08y = 2100

0.02y = 2100 - 1680

0.02y = 420

y = 420/0.02

y = 21000

Put 21000 for y in eq 3 to get;

x = 28000 - 21000

x = 7000

Thus amount invested in each account is;

At 6% interest rate, amount invested = $7000

At 8% interest rate, amount invested = $21000

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: