On a coordinate plane, a curved line with a minimum value of (0.8, negative 11.4) and maximum values of (negative 1.6, 56) and (2, 0), crosses the x-axis at (negative 2.5, 0), (0, 0), and (2, 0), and crosses the y-axis at (0, 0). What is the local maximum over the interval [–3, 1.5] for the graphed function? A. 0 B. 56 C. –11.4 D. 2

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step-by-step explanation:

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3