A box of chocolates contains 18 chocolate squares, tens of the square are milk chocolate, 5 are dark chocolate, and 3 are. white Chocolate. If Christina randomly chooses a chocolate out of the box what is the probability of her choosing a white chocolate square randomly select a milk chocolate first, replace it, and then select a white chocolate?

0.167 ; 0.093

Step-by-step explanation:

Given that:

Total number of chocolate squares = 18 of which÷

Number of milk chocolate square = 10

Dark chocolate square = 5

White chocolate square= 3

Probability of choosing a white chocolate square :

Probability = required outcome / Total possible outcomes

Required outcome = white chocolate square = 3

Number of chocolate square = 18

P(choosing a white chocolate square) = 3 / 18 = 1/6 =

B) probability of randomly selecting a milk chocolate first, replace it, and then select a white chocolate?

With replacement :

First pick :

Number milk chocolate = 10

P(choosing a milk chocolate) = 10/18 = 5/9

Second pick:

Number of white chocolate = 3

P(choosing a white chocolate) = 3 / 18 = 1/6

Hence, since both probabilities are independent :

P(choosing milk, then white chocolate) :

(5/9 × 1/6) = 5/54 = 0.0925 = 0.093

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

im pretty sure its

(8,15)

step-by-step explanation: