A ball is thrown from an initial height of 2 feet with an initial upward velocity of 37 fts. The bal's height h (in feet) after t seconds is given by the following. h=2+37-16
Find all values of t for which the ball's height is 22 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
seconds
х
5
?
initial
height
ground

a. -0.3 > -0.33

1010: 3030

is it i think

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.