Building A is 226 meters taller than building B. If the height of building A is subtracted from twice the height of building B, the result is 276 meters. How tall is each skyscraper?

Building A is 338 meters taller than building B. If the height of building A is subtracted from twice the height of building​ B, the result is 131 meters. How tall is each​ skyscraper?

Let a = the height of building A and b = the height of building B.

You get a = b + 338

if you subtract the height of building A from twice the height of building B, then you get:

2b - a = 131.

You have 2 equations to be solved simultaneously.

They are:

a = b + 338

2b - a = 131

in the second equation, replace a with its equivalent value from the first equation to get:

2b - (b + 338) = 131

simplify to get 2b - b - 338 = 131

combine like terms to get b - 338 = 131

Add 338 to both sides of the equation to get b = 469.

That's the height of building B.

Since building A is 338 meters higher than that, then building A must be 807 meters high.

You get building A is 807 meters high and building B is 469 meters high.

Building A is 807 - 469 = 338 meters higher than building B.

If you subtract the height of building A from twice the height of building B, you get 2 * 469 - 807 = 938 - 807 = 131 meters difference.

Solution to the first question looks good.

Building A is 807 meters high and building B is 469 meters high.

Second question:

During his tennis career in singles​ play, John won 33 fewer tournament A titles than tournament B titles and 22 more tournament C titles than tournament B titles. If he won 20 of these titles​ total, how many times did he win each​ one?

Let a = number of tournament A titles won.

Let b = number of tournament B titles won.

Let c = number of tournament C titles won.

Since total number tournament titles won is 20, you get:

a + b + c = 20

since he won 33 fewer tournament A titles than tournament B titles, you get:

a = b - 33

since he won 22 more tournament C titles than tournament B titles, you get:

c = b + 22.

Replacing a and c with their equivalent values from the first 2 equations, you get the third equation becoming:

b - 33 + b + b + 22 = 20

combine like terms to get 3b - 11 = 20

add 11 to both sides to get 3b = 31

Divide both sides by 3 to get b = 10 and 1/3.

Since a = b - 33, this makes a = - (22 and 2/3).

Since c = b + 22, this makes c = 32 and 1/3.

a + b + c = 20, but

An is negative which can't be, indicating there is something wrong with the equation.

I suspect that the total number of tournaments won have to be a number greater than or equal to 33 in order for a to be greater than or equal to 0.

i don't believe there is a valid solution to this problem the way it is presented.

first of all, the value of b was not an integer.

second of all, the value of a is negative.

these are two indications that there is something wrong with the equation the way it is presented.

the answer is a

step-by-step explanation:

because your just changing the position of where the shape is

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.