Arectangle has a n area of 20 meters. if the perimeter of the rectangle is 24 meters , what are the length and width of the rectangles .

Area = 20 meters square 
perimeter = 24 meters 

l*w=20
2l+2w=24  divide both sides by 2 and will get 

l+w=12 => l = 12-w substitute inside the first equation of area 

(12-w)*w = 20

12w -w^2 =20 

w^2 -12w +20 = 0

D = 144 -4*20 = 144-80 = 64

w_1,2 = (12 +/- 8)/2 = 20/2 = 10 and 4/2 = 2 

l = 12 -w 

l_1 = 12 - 10 = 2 
l_2 = 12 - 2 = 10 

so from these result that the length of the rectangle equal 10 and the width of the rectangle equal 2 

hope helped 

The answer is c. 7 (i think) i’m almost sure though