If AC=3x, AB=15, and BC=2x-1, how could we solve for x? A. Set 3x=15

B. Set 3x=2x-1

C. Set 3x+15=2x-1

D. Set 3x=15+(2x-1)

E. Not enough information

A. 3x = 15

or, x = 15/3

or, x = 5

B. 3x = 2x-1

or, 3x-2x = -1

or, x = -1

C. 3x+15 = 2x-1

or, 3x-2x = -1-15

or, x = -16

D. 3x = 15+(2x-1)

or, 3x = 15+ 2x-1

or, 3x-2x = 14

or, x = 14

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step-by-step explanation:

(x+3)(x+7)

step-by-step explanation: