Anna applies the brakes of her car , the car slows down uniformly from 15 m / s to rest in 2.5 s . How many metres before a stop sign must she apply her brakes ?

given information

u=15m/ sec

v=0

t=2.5 sec

s=?

acceleration will be negative.

applying v=u+at

0=15+a x 2.5

-15=2.5a

a=-15/2.5

a= - 6m/sec

applying v^2= u^2+2as

0= 225+2x (-6) x s

s=225/12= 18.75 metre.

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6 meters

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The answer is 6 meters. Hope this helps!

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