Find the surface area of a square pyramid if the area of the base is 324 cm squared and the height is 40 cm.

heighth = 324 cm

slant heights = 324.61669704438 cm

side lengtha = 40 cm

lateral edge lengthe = 325.23222472566 cm

1/2 side lengthr = 20 cm

volumeV = 172800 cm^3

lateral surface areaL = 25969.33576355 cm^2

base surface areaB = 1600 cm^2

total surface areaA = 27569.33576355 cm^2

Step-by-step explanation:

Total Surface Area of a square pyramid:

A = L + B = a^2 + a√(a^2 + 4h^2))

A = a(a + √(a^2 + 4h^2))

Agenda:

h = height

s = slant height

a = side length

e = lateral edge length

r = a/2

V = volume

L = lateral surface area

B = base surface area

A = total surface area

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225