How many chirps can you expect a cricket to make in 1 min when the outside temperature is 50 ° F ? ( it’s not 75)

F = n/4 + 37, for F = 50

50 = n/4 + 37

Subtract 37 from both sides

13 = n/4

Multiply both sides by 4

52 = n

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50