Someone please help fast, I am really lost with the law of logarithms and need help with these questions in picture

We'll use the following log rules

Part 1

Work Shown:

Ln(100) = Ln(4*25)

Ln(100) = Ln(2*2*5*5)

Ln(100) = Ln(2)+Ln(2)+Ln(5)+Ln(5) ... using log rule 1

Ln(100) = a+a+c+c

Ln(100) = 2a + 2c

Part 2

Work Shown:

Ln(2.4) = Ln(24/10)

Ln(2.4) = Ln[ (2*2*2*3)/(2*5) ]

Ln(2.4) = Ln[ (2*2*3)/5 ]

Ln(2.4) = Ln(2*2*3) - Ln(5) ... using log rule 2

Ln(2.4) = Ln(2)+Ln(2)+Ln(3) - Ln(5) using log rule 1

Ln(2.4) = a+a+b-c

Ln(2.4) = 2a+b-c

Part 3

Work Shown:

Ln(0.003) = Ln(3/1000)

Ln(0.003) = Ln[ 3/( 10^3) ]

Ln(0.003) = Ln(3) - Ln(10^3) ... log rule 2

Ln(0.003) = Ln(3) - 3*Ln(10) ... log rule 3

Ln(0.003) = Ln(3) - 3*Ln(2*5)

Ln(0.003) = Ln(3) - 3*( Ln(2) + Ln(5) ) ... log rule 1

Ln(0.003) = b - 3*( a + c )

Ln(0.003) = b - 3a - 3c

Ln(0.003) = -3a + b - 3c

Part 4

Work Shown:

All logs shown for this part are in base 2

log(5400) = log(54*100)

log(5400) = log(6*9*4*25)

log(5400) = log(2*3*3*3*2*2*5*5)

log(5400) = log(2^3*3^3*5^2)

log(5400) = log(2^3)+log(3^3)+log(5^2) ... log rule 1

log(5400) = 3*log(2)+3*log(3)+2*log(5) ... log rule 3

log(5400) = 3a + 3b + 2c

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

it has changed from the width and the height.

step-by-step explanation: