Return to the credit card scenario of exercise 12 (section 2.2), and let c be the event that the selected student has an american express card. in addition to p(a) = .6, p(b) = .4, and p(a > b.= .3, suppose that p(c) = .2, p(a > c) = .15, p(b >
c.= .1, and p(a > b >
c.= .08.
a. what is the probability that the selected student has at least one of the three types of cards?
b. what is the probability that the selected student has both a visa card and a mastercard but not an american express card?
c. calculate and interpret p(b u
a. and also p(a u b).

e.

step-by-step explanation:

because there are always 10 numbers in a phone number.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

2 pecks

step-by-step explanation:

step-by-step explanation:

d would equal 12