Statistic Company A Company B Arithmetic Mean 500 600 Median 500 500 Mode 500 300 Standard Deviation 40 20 Mean Absolute Deviation 32 16 Quartile Deviation 25 14 Range 240 120 Sample Size 100 80 The middle 95% of the wires from Company A tested between () and (upper) limit. Record ONLY the lower limit as a whole number.

Idon’t know the answer to this

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60