Roberto invested a total of $10,000, part at 6% and part at 9%. How much did he invest in the HIGHER interest account if the total interest earned in one year was $810?

Given :

Roberto invested a total of $10,000, part at 6% and part at 9%.

To Find :

How much did he invest in the higher interest account if the total interest earned in one year was $810 .

Solution :

Let , x amount is invested in 6% interest .

Therefore , 10000-x amount is invested in 9% interest .

Now , total interest is $810 .

We know , simple interest is given by :

So ,

Solving above equation , we get :

.

Therefore , investment on higher i.e 9 % is 10000-3000 = $7000 .

Hence , this is the required solution .

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%