Consider the experiment of tossing three coins. What is the probability of getting anything but one head and two tails?

5/8

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

The number of trials is n = 3.

The number of heads is r = 1.

The probability of heads is p = ½.

The probability of getting 1 heads and 2 tails is:

P = ₃C₁ (½)¹ (1 − ½)³⁻¹

P = 3 (½) (½)²

P = 3/8

So the probability of not getting 1 heads and 2 tails is:

1 − P = 5/8

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.