Jenny has some nickels and some dimes. The value of the coins is $1.65.
There are 12 more nickels than dimes.
How many of each kind of coins does
Jenny have?

7 dimes and 19 nickels

Step-by-step explanation:

d = dimes

n = nickels

The total amount is

.05n + .1d =1.65

He has 12 more nickels than dimes

12+d = n

Substitute this into the first equation

.05 (12 +d)  + .1d =1.65

.6 + .05d +.1d = 1.65

Combine like terms

.6 + .15d = 1.65

Subtract .6 from each side

.15d = 1.65-.6

.15d = 1.05

Divide by .15

.15d/.15 = 1.05/.15

d = 7

Now find n

12+d = n

12+7 = n

19 = n

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10